String Operations using Operator Overloading (C++)
/*write a program to perform string operations = equality == string copy + concatenation >> reverse << display palindrome function function to find occurence of substring use operator overloading*/ #include<iostream> #include<string.h> #include<iomanip> using namespace std; class strings { char str[100]; public: void getdata() { cout<<"enter string\t"; cin>>str; } void showdata() {cout<<str<<endl;} int operator ~(); int operator =(strings s2); void operator ==(strings s2); friend void operator +(strings s1,strings s2); friend ostream &operator <<(ostream &output,strings &s1) { output<<s1.str; return output; } void operator >>(strings &s1); friend void operator *(strings s1); friend void operator /(strings s1,strings s2); }; //string length int strings::operator ~() { int i=0; while(str[i]!=’\0’) i++; return i; } //string compare int strings::operator =(strings s2) { int i=0; while(str[i]==s2.str[i] && i<~s2) i++; if(i==~s2) return 1; else return 0; } //copy void strings::operator ==(strings s2) { for(int i=0;i<=~s2;i++) str[i]=s2.str[i]; } //concat void operator +(strings s1,strings s2) { int i,j,k=0; strings s3; for(i=0;i<~s1;i++) { s3.str[k]=s1.str[i]; k++; } for(j=0;j<~s2;j++) { s3.str[k]=s2.str[j]; k++; } cout<<s3.str<<endl; } //reverse void strings:: operator >>(strings &s1) { int len=~s1; for(int i=0;i<=len/2;i++) { char t=s1.str[i]; s1.str[i]=s1.str[len-i-1]; s1.str[len-i-1]=t; } } //palindrome void operator *(strings s1) { strings s3; s3==s1; s3>>s3; if((s3=s1)==1) cout<<"palindrome\n"; else cout<<"not palindrome\n"; } //find substring void operator /(strings s1,strings s2) {//s2=substring int flag=0; for(int i=0;i<~s1;i++) { if(s2.str[0]==s1.str[i]) { flag++; for(int j=1;j<=~s2;j++) if(s2.str[j]==s1.str[i+j]) flag++; } } if(flag==~s2) cout<<"substring exists\n"; else cout<<"not found\n"; } int main() { strings s1,s2; int choice; char c; cout<<setw(20)<<"STRING OPERATIONS"<<endl; cout<<"1.accept and display string \n2.check for equality\n3. copy string\n 4.concatenate strings \n5.reverse string\n6.check if a string is a palindrome\n7.search for a substring occurence\n"; do { cout<<"enter choice\t"; cin>>choice; if(choice==2) { cout<<"enter first string\n"; s1.getdata(); cout<<"enter second string\n"; s2.getdata(); if((s1=s2)==1) cout<<"strings are same\n"; else cout<<"strings are different\n"; } if(choice==3) { cout<<"enter string to copy\n"; s2.getdata(); s1==s2; cout<<"contents copied to another string\n"; cout<<"contents of copy string is :\t"; cout<<s1<<endl; } if(choice==4) { cout<<"enter destination string:\n"; s1.getdata(); cout<<"enter source string:\n"; s2.getdata(); s1+s2; } if(choice==1) { s1.getdata(); cout<<"string is:\t"; cout<<s1<<endl; cout<<~s1; cout<<endl; } if(choice==5) { s1.getdata(); s1>>s1; cout<<"string after reversing is\t"; cout<<endl; cout<<s1<<endl; } if(choice==6) { s1.getdata(); *s1; } if(choice==7) { cout<<"enter main string\n"; s1.getdata(); cout<<"enter substring\n"; s2.getdata(); s1/s2; } cout<<"do you want to continue(y/n)?"; cin>>c; }while(c==’y’); return 0; }