Method Overloading in Java

Functions are called methods in Java

• You can create a number of methods with same name in Java. But, you must distinguish them by:
  • Number of arguments
  • Arguments data type

Understanding through Code

import java.util.Scanner;    public class MethodOverloading {  	public static void main( String[] args ){    		String s1 = getInput("Enter value 1: ");  		String s2 = getInput("Enter value 2: ");  		String s3 = getInput("Enter value 3: ");    		double result = addValues(s1, s2);  		System.out.println("The answer is: " +result);    		double result1 = addValues(s1, s2, s3);  		System.out.println("The answer for 3 values is: " +result1);    		double result2 = addValues(s1, s2, s3, s1, s2, s3);  		System.out.println("The answer for n values is: " +result2);    	}    	//Marked static so that the method can be directly called from static main method  	static String getInput(String ip) {		//String => this method returns String  		System.out.println(ip);  		Scanner sc = new Scanner(System.in);    		return sc.nextLine();  	}    	static double addValues(String s1, String s2) {  //double => this method returns double  		double d1 = Double.parseDouble(s1);  		double d2 = Double.parseDouble(s2);  		double result = d1 + d2;  		return result;  	}    	//Method overloading -> adding another argument  	static double addValues(String s1, String s2, String s3) {   		double d1 = Double.parseDouble(s1);  		double d2 = Double.parseDouble(s2);  		double d3 = Double.parseDouble(s3);  		double result = d1 + d2 + d3;  		return result;  	}    	//Method for non-deterministic number of arguments  	static double addValues(String ... values) { //user can pass as many values as he wants  		double result = 0;  		for( String value: values ) {  //for each loop  			double d = Double.parseDouble(value);  			result += d;  		}  		return result;  	}    }

Output

• Enter value 1:
• 2
• Enter value 2:
• 2
• Enter value 3:
• 2
• The answer is: 4.0
• The answer for 3 values is: 6.0
• The answer for n values is: 12.0